Comparing vector elements by percentage
4 visualizzazioni (ultimi 30 giorni)
Mostra commenti meno recenti
Angle=[5 10 20 60 180 190 195 300 310], these angles determine the possible directions of robots. If there are 2 robots starting with the same angle or plus minus 5%(5 degrees) they will make collision. I'd like to have the result in on vector such that:[2 2 1 1 1 2 2 1 1]. Any help?
5 Commenti
Stefan Raab
il 2 Nov 2015
Modificato: Stefan Raab
il 2 Nov 2015
Hello,
the codeline
collision(i)= Angle(inToleranceIndexes)
won't work, if inToleranceIndexes has more than one value==1. Then Angle(inToleranceIndexes) i.e. is [300 310] and you can't assign a vector to a single element as you do with collision(i).
But a question in general: You say tolerance is 0.05*targetValue, that means your tolerance increases with increasing start-angle. Is this really how it is supposed to be?
Best regards, Stefan
Risposte (1)
Image Analyst
il 2 Nov 2015
As mentioned in your duplicate question there will be no collision unless you have different starting points. And all your code does is tell you that each angle interferes/collides with no other angle except itself, which is pretty useless.
0 Commenti
Vedere anche
Categorie
Scopri di più su Resizing and Reshaping Matrices in Help Center e File Exchange
Prodotti
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!