For loop assignment problem

I have a struct with 85 fields. I want to copy data from the fields into a matrix called "one". Here is my code:

one=nan(85,2);
fields=fieldnames(s);

for i = 1:numel(fields)
    len=find(s.(fields{i})==0)/4;
    one(i)=s.(fields{i})(len-1,3:4);
end

This generates the "in an assignment A(:) = B" error. If I remove the subscript 'i' from 'one' it works, but then it overwrites the data on each loop, instead of storing it.

Answer 1

[Adam]

one(i,:)=s.(fields{i})(len-1,3:4);

should work if I understand the problem correctly. Judging by your pre-sizing I assume the right-hand side of that equation is a 1-by-2 array which needs to be assigned to something of the same size on the left-hand side using row and column indices.

[Cary]

Thank you!