Syntax Issue in If Statement Using Handles

2 visualizzazioni (ultimi 30 giorni)
Jay
Jay il 11 Apr 2016
Commentato: Jay il 11 Apr 2016
I am trying to write an if statement in a function, to determine if the handles values are of valid type, as per the stipulation in the texts written above said handles in the GUI.
For handle 'edit1' I have written:
if handles.edit1 == NaN
set(handles.edtit2, 'enable', 'off') && set(handles.listbox1, 'string', 'Date must be of stated syntax')
else set(handles.edit2, 'enable', 'on')
end
During runtime the code skips to else not flagging
if handles.edit1 == Nan
as true thus setting the 'handles.edit2' off and having the error showing in listbox1.
What is wrong with my if statement?

Risposta accettata

Stephen23
Stephen23 il 11 Apr 2016
Modificato: Stephen23 il 11 Apr 2016
You cannot test for equality of NaN's, because as the documentation clearly states, NaN's are not equal to each other. Use isnan instead:
>> handles.edit1 = NaN;
>> handles.edit1 == NaN
ans =
0
>> isnan(handles.edit1)
ans =
1

Più risposte (1)

Walter Roberson
Walter Roberson il 11 Apr 2016
Use ishghandle() instead testing for NaN .

Categorie

Scopri di più su Graphics Object Programming in Help Center e File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by