Azzera filtri
Azzera filtri

“if” statement using “or” operator.

3.059 visualizzazioni (ultimi 30 giorni)
Sarah
Sarah il 2 Feb 2012
Commentato: Lewis Waswa il 9 Gen 2023
Hello everyone,
I have a very simple question....and I have been working on it for some time but cannot figure it out. This is essentially what I would LIKE to say:
for r = 1:length(FreqSec)-1
if FreqSec(1,r+1) > FreqSec(r)*1.01 "OR" FreqSec(1,r+1) <FreqSec(r)*0.99
LagStart = [FreqSec(1,r) r];
break;
end
end
FreqSec is a vector with lots and lots of values....generally within the range of 0.99 and 1.01, except for in a certain interval. I want to detect the exact index point at which the values start changing from the 0.99 to 1.01 range.
Thanks for the help in advance :)

Risposta accettata

Walter Roberson
Walter Roberson il 3 Feb 2012
if FreqSec(1,r+1) > FreqSec(r)*1.01 | FreqSec(1,r+1) <FreqSec(r)*0.99
or
if FreqSec(1,r+1) > FreqSec(r)*1.01 || FreqSec(1,r+1) <FreqSec(r)*0.99
The first of these is more general. The second of these, , is the short-circuiting OR that does not bother to evaluate the second expression if it already knows the final result after the first operation. The operator can only be used between expressions that produce scalar outputs.
  3 Commenti
Lewis Waswa
Lewis Waswa il 9 Gen 2023
A quick question, does this mean that the | evaluattes all the conditions?

Accedi per commentare.

Più risposte (2)

Geoff
Geoff il 3 Feb 2012
So you want the last index within the valid range?
I don't know why you are multiplying by 1.01 and 0.99. Perhaps you have described the problem incorrectly or that is the cause of your difficulties. What I think you are trying to do is this:
idx = find( FreqSec >= 0.99 & FreqSec <= 1.01, 1, 'last' )
LagStart = [FreqSec(1,idx) idx];
Or, since it's symmetric:
idx = find( abs(FreqSec-1) <= 0.01, 1, 'last' )
If instead you want the index of the first out-of-range value, use:
idx = find( abs(FreqSec-1) > 0.01, 1, 'first' )
The parameter 'first' is optional, but good for clarity.
-g-
  1 Commento
Geoff
Geoff il 3 Feb 2012
Oops, those statements with 'last' are incorrect. You are probably better off doing the 'first' statement and subtracting 1.

Accedi per commentare.


Rehman Tabasum
Rehman Tabasum il 30 Apr 2021
i=5
while i>=-1
pause(1)
fprintf('%d\n',i)
i=i-1
if i==0
break
end
end
this is my code for the start button gui for countdown timer so anyone know how to stop coutdown timer when it is runnnig

Categorie

Scopri di più su Interactive Control and Callbacks in Help Center e File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by