max and min complex number
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i have set that contain complex number, then i get the greatest value using max function and get the smallest value using min function. For example the max value is -0.0115230+0.0474206i and the minimum value is 0.0026796 + 0.0006868i But if i give this command -0.0115230+0.0474206i > 0.0026796 + 0.0006868i it get the result ans=0. So, how did it happen ? should the result is ans=1 ?? please help. i am very confused
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Guillaume
il 7 Giu 2016
It can be proven that complex numbers cannot be ordered (under the definition of an ordered field). That means that you cannot compare complex numbers.
5 Commenti
Guillaume
il 14 Giu 2016
Complex numbers are the same as points on a 2D plane. Given a set of points in a plane, can you tell which is the minimum and which is the maximum? No, the concept does not make sense. Same for complex numbers.
Similarly, given a set of points, can you tell if another point is in the range of these points? Well, first you have to define what you mean by the range of a set of points. Until you do that, we can't help you.
Possibly, you can define a point in range of a set of point if it is within the convex hull of the set, but only you can decide that.
Più risposte (2)
Azzi Abdelmalek
il 7 Giu 2016
Modificato: Azzi Abdelmalek
il 7 Giu 2016
If x1=1.1+2*i and x2=1+2.1*i What is the smallest number ? You can't compare two complex numbers, you can compare their modulus
abs(x1)>abs(x2)
I think max and min function, in your case, are finding the max and min of abs(your_array)
9 Commenti
Guillaume
il 9 Giu 2016
"If you wish to create an order then you can use the magnitude."
You can, but that ordering is not compatible with addition and multiplication. So, with that ordering, if you have
z1 < z2
You cannot assume that
z1 + c < z2 + c %c a complex constant
z1 * c < z2 * c, with c > 0 a complex constant
Iain
il 7 Giu 2016
Max is calculating the absolute value, and then taking the maximum value, despite being negative.
Greater than is taking the value farthest from negative infinity.
7 Commenti
Torsten
il 9 Giu 2016
Modificato: Torsten
il 9 Giu 2016
@eliz, I asked because your question had already been answered several times and it seemed to me you were not satisfied with these responses. So my guess was that you tried to ask something different, something we did not yet understand.
Best wishes
Torsten.
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