converting array to single

i have this output:

output = dial ('1FUNDOG4YOU')

output =

       1     3     8     6     3     6     4     4     9     6     8
  (1 X 11) cell

but this is what i want

output :13863644968 

           (1X 1)

I've tried all sort of ridiculous stuff, str2num and the likes but nothing works . any idea on what to do to make the conversion happen? thanks

Answer 1

[Stephen23]

If the elements of the cell array are numeric scalars:

>> C = {1,3,8,6,3,6,4,4,9,6,8};
>> sprintf('%d',C{:})
ans = 13863644968

Or if they are strings:

>> C = {'1','3','8','6','3','6','4','4','9','6','8'};
>> sprintf('%s',C{:})
ans = 13863644968

Note that this string has size 1x11 (strings are not size 1x1 in MATLAB). If you need it to be stored in a 1x1 array, then you can put it inside a cell.

[OLUBUKOLA ogunsola]

works but its comes out as char , but my objective is to get a uint64 class. when i use uint64(ans), it gives me a 1X11

[Azzi Abdelmalek]

C = {1,3,8,6,3,6,4,4,9,6,8}
C=sprintf('%d',C{:})
C=uint64(str2num(C))

[OLUBUKOLA ogunsola]

perfect ! thanks

Answer 2

[Walter Roberson]

Be careful, str2num() will create double precision with only 53 bits of precision. If you need the full 64 bits of precision you will need a different calculation.

C = {1,3,8,6,3,6,4,4,9,6,8};
Cv = uint64([C{:}]);
output = sum( Cv .* (uint64(10).^uint64(length(Cv)-1:-1:0)), 'native' );

[OLUBUKOLA ogunsola]

it actually works , problem now is testing for conditions. input should be only numbers and letters . I've tried ~isnumber , if ~isletter , isstrprop but nothing works

[Stephen23]

@OLUBUKOLA ogunsola: read the isstrprop documentation:

>> inp = '1FUNDOG4YOU';
>> all(isstrprop(inp,'alphanum'))
ans =  1
>> inp = '!%()="';
>> all(isstrprop(inp,'alphanum'))
ans = 0

And read about assert.

[OLUBUKOLA ogunsola]

thanks for the info . since all(isstrprop(inp,'alphanum'))returns ans=1 or 0, i did this

x=all(isstrprop(inp,'alphanum'))

then

if x=1

the code else

output =0

but it still doesnt work. Debugging shows that the program continues with the program even when x==0. maybe its something in my code that is causing that. meanwhile I'm studying the assert ,hopefully that will work

[Stephen23]

The function isstrprop and all both return logical values, so you don't need to compare them to anything. They are already boolean values, that can be used directly in an if statement:

if all(isstrprop(...))
    ...
else
    ...
end

No testing for "==0" is required.

[OLUBUKOLA ogunsola]

problem with assert is it outputs an error , i don't want that i want output =0 . so i wrote the code this way

assert(isa(testStr,'alphanum'),'output=0.') but gets an error :

Error using dial (line 6) output=0

[OLUBUKOLA ogunsola]

this is the code i wrote :

function output = dial (testStr)

c = containers.Map({'0','1','2','3','4','5','6','7','8','9','A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z'}, ...
    [0,1,2,3,4,5,6,7,8,9,2,2,2,3,3,3,4,4,4,5,5,5,6,6,6,7,7,7,7,8,8,8,9,9,9,9]) ;

testOut = NaN(1,numel(testStr)) ;

x=all(isstrprop('testStr','alphanum'));

     if x==1      

for ii = 1:numel(testStr);

      testOut(ii) =  c(strcat(testStr(ii)));

      C=sprintf('%d',testOut(:));

      C=uint64(str2double(C));

end

   output=C ;

     else

      output=0;

     end 

end