finding a string in a cell array
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wesso Dadoyan
il 22 Giu 2016
Commentato: Azzi Abdelmalek
il 22 Giu 2016
ids1='519448(EPS1MN)' '519448(EPS2MN)' '519448(EPS3MN)' '519448(EPS4MN)' '519448(EPS5MN)' '519448(LTMD)' '519448(P)' '519448(DPS)' '519448(EPS)'
I want to find the cell that has embedded in it EPS1MN ,....EPS5MN
writing the following codes:
x2a=find(~isempty(strfind(ids1,'EPS1MN'))); % select rows.
x2b=find(~isempty(strfind(ids1,'EPS2MN')));
x2c=find(~isempty(strfind(ids1,'EPS3MN')));
x2d=find(~isempty(strfind(ids1,'EPS4MN')));
x2e=find(~isempty(strfind(ids1,'EPS5MN')));
is returning a value of 1 for x2a...x2e which is obviously wrong since the answers should be 1,2,...5
I am wondering what went wrong?
2 Commenti
Azzi Abdelmalek
il 22 Giu 2016
wesso commented
the two answers work well with EPS1...EPS5 but they fail to identify the cell when the cell is (P). (i.e I want the answer to identify cell '519448(P)' and gets an answer of 7. Any help with this?
Azzi Abdelmalek
il 22 Giu 2016
If we give you the solution with (P), you will ask again it's not working with (T) or another string!
Risposta accettata
Azzi Abdelmalek
il 22 Giu 2016
ids1={'519448(EPS1MN)'
'519448(EPS2MN)'
'519448(EPS3MN)'
'519448(EPS4MN)'
'519448(EPS5MN)'
'519448(LTMD)'
'519448(P)'
'519448(DPS)'
'519448(EPS)'}
out=find(~cellfun(@isempty,regexp(ids1,'EPS[12345]MN')))
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