Finding data off excel sheet

In the excel sheet attached, the data is 3 different sensors 0,1 and 2(1st column), their voltage(2nd column) and time of the reading(3rd column). I'm struggling to find a way to seperate the full data set into one set of voltage readings and time readings for each sensor. This is what I have
A = xlsread('forcetest.csv');
idx1 = find(A == 0)
I used xlsread just because I think it is easier. I know I have to used the find function, this code I have so far just finds what rows are the censor 0, how to I get it to give me all those rows with the given voltage and time data? Do I have to use a for-loop?

7 Commenti

Bryce Keeler
Bryce Keeler il 4 Lug 2016
Modificato: Bryce Keeler il 4 Lug 2016
Not entirely sure what you're asking for, but I think what you mean is you want all the data associated with the "Sensor 0" rows? In that case the the code you are looking for is
idx1 = A(find(A==0),:);
yes i want all the data for sensor 0, I can just use that code to get all the data for 1 and 2
this is right thank you
Good to hear! Would you mind accepting it as an answer then?
He could if you post it below AS and answer, instead of here as a comment.
Yea I can't accept it since its a comment.
Well like I said in my answer it wouldn't have worked anyway since it finds 0's anywhere, not just in column 1.

Accedi per commentare.

 Risposta accettata

Try this:
A = xlsread('forcetest.csv');
% Extract column 1 which has the sensor IDs.
col1 = A(:, 1);
% Find which rows have value 0, meaning this row is for sensor #0.
sensor0Rows = find(col1 == 0);
% Extract only those rows for sensor #0.
array0 = A(sensor0Rows, :);
% Get voltage and time separately, in case that's wanted.
voltages = A(sensor0Rows, 2); % From column 2
times = A(sensor0Rows, 3); % From column 3
Note that find(A==0) won't work since it finds 0's anywhere, not just in column 1. So if you had a 1 or 2 in column 1 but a 0 in column 2, then it would pick out this row even though it shouldn't.

Più risposte (0)

Categorie

Scopri di più su MATLAB in Centro assistenza e File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by