Azzera filtri
Azzera filtri

How can solve the problem? please!

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abduall hassn
abduall hassn il 27 Ago 2016
Modificato: abduall hassn il 3 Nov 2016
p=[148
249
357
547
854
1
1184
996
966
679
586
503
281
1
110
89
58
68
28
19
16
6
13
7
4
2
1
12]
this equation
and this code
xn = zeros(size(p))
mx=max (p(2));
mn=min (p(1));
mmd=mx-mn;
for i=1:(P,1)
xn(i,:)=(p(i,:)-mn)./(mmd)*(mx-mn)+mn
end
p is data for normalization
I applied min and max equation that is mention above.
When I applied the code the output wrong, please can you tell where the wrong in the code
  3 Commenti
abduall hassn
abduall hassn il 27 Ago 2016
I found the proper equation for max and min normalization
- The previous one the normalization is default between [o,1]. But, in this we select and values as mention in equation *(mx-mn)+mn
Walter Roberson
Walter Roberson il 27 Ago 2016
Is the previous question solved relative to what you asked there? If so then you should Accept one of the solutions. But if what you were wanting was just to correct the question, then you should have edited that one instead of starting a new question.

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Risposta accettata

Pawel Ladosz
Pawel Ladosz il 27 Ago 2016
Modificato: Pawel Ladosz il 27 Ago 2016
Hi Abudlla,
It appears the mistake is in:
(mx-mn)+mn
this line should be (new_max_a-new_min_a)+new_min_a and in your code it is: (max_a+min_a)+min_a.
In other words you are lacking variables for new_max_a and new_min_a.
  2 Commenti
abduall hassn
abduall hassn il 27 Ago 2016
Dear this variable we can write new _max and new_min or min and max
I am asking the code dosn't display the output properly
abduall hassn
abduall hassn il 27 Ago 2016
I got the error, the error was xn(i,:) and as mention dear Pawel Ladosz

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