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Creating tables using loops

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Raahul Palanivel Uma
Raahul Palanivel Uma il 10 Ott 2016
I am performing an Interpolation between a set of values (200,190,180,160) and I want to store the results in a single Matrix. I'm have used a for-Loop so that the Interpolation is done between all the values in my Input Array. If I interpolate 9 values between each Input value, I must have a Matrix with 41 values (200,199,198...160) as the end result. But I have 44 values in the Matrix since each time the Loop executes, the Interpolation is carried out between 200 & 190, then 190 & 180 and so on. I want the each column of Interpolation step to be replaced by the first column of the next Interpolation step. If anyone could suggest me a solution, it would be very helpful. I Need to know how to proceed with the incrementation and store the final result in a single Matrix. Thanks in advance Raahul
  2 Commenti
KSSV
KSSV il 10 Ott 2016
Modificato: KSSV il 10 Ott 2016
If the number of rows or columns differ for every interpolation how you expect them to be saved in matrix?
Raahul Palanivel Uma
Raahul Palanivel Uma il 10 Ott 2016
the number of rows and columns are constant during each Interpolation step.

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Risposte (1)

Pritesh Shah
Pritesh Shah il 10 Ott 2016
In each Interpolation step, A(end)=[];
This should work.

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