Azzera filtri
Azzera filtri

How to plot this function?

1 visualizzazione (ultimi 30 giorni)
Michaël
Michaël il 14 Mar 2011
Hello,
Could you please help me plot this function with Matlab ?
<http://img638.imageshack.us/img638/3205/fonction.png >
I'm a beginner. Your help will be valuable to me.
Many thanks

Risposta accettata

Matt Fig
Matt Fig il 15 Mar 2011
If you want to do it manually, try this:
f = @(z) quadv(@(x) (1/(3*sqrt(2*pi)))*exp(-(x-30).^2/18),z,100);
Z = 0:.25:50;
G = zeros(1,length(Z));
for ii = 1:length(Z)
G(ii) = f(Z(ii));
end
plot(Z,G)
xlabel('z')
ylabel('(1/\surd(2*pi))\inte^{-(x-30)^2/18}')

Più risposte (4)

Matt Tearle
Matt Tearle il 14 Mar 2011
Take a look at erfc. A simple change of coordinates should get you there.
Then plotting can be done by
x = linspace(xmin,xmax,npoints);
y = constant*erfc(x);
plot(x,y)
  2 Commenti
Michaël
Michaël il 14 Mar 2011
Thank you for your answer.
But can't I put my function directly (without going through a pre-determined function)?
Thanks
Matt Tearle
Matt Tearle il 15 Mar 2011
Why would you want to? This function is defined via an improper integral, which means you'll have to do an infinite-domain integral for each value of z. This will be slow and will introduce all sorts of numerical errors. On the other hand, the error function is a well-known function -- its implementation in MATLAB is stable and tested. Why reinvent the wheel?
But if you really want to, you can use something like quad to do the integral.

Accedi per commentare.


Michaël
Michaël il 14 Mar 2011
Thank you for your answer.
But can't I put my function directly (without going through a pre-determined function)?
Thanks

Michaël
Michaël il 14 Mar 2011
How can't we put : (-1+x.)^2 ?

Michaël
Michaël il 15 Mar 2011
Thank you very much !!!

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by