how to convert column cell to row cell?

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sumana
sumana il 26 Gen 2017
Commentato: jaweria kainat il 16 Lug 2018
Hi,
For example I have a 3x1 cell matrix like this. {[1,2,3] [4,5,6] [7,8,9]}; where every element is a 1x3 matrix.
I want to convert the row cells to 3x1 column cells like this {[1;2;3] [4;5;6] [7;8;9]};
How do I do this ? Thank you.
  1 Commento
jaweria kainat
jaweria kainat il 16 Lug 2018
suppose i have 2 columns.how i can convert them into rows?

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Jan
Jan il 26 Gen 2017
Modificato: Jan il 27 Gen 2017
Or a loop:
for k = 1:numel(C)
C{k} = C{k}.';
end
[EDITED] Accroding to your comment:
M = [1 2 3; 4 5 6; 7 8 9];
C = mat2cell(M.', 3, [1,1,1]).';
{[1;2;3];
[4;5;6];
[7;8;9]}
Or again with a simple loop:
C = cell(3, 1);
for k = 1:3
C{k} = M(k, :).';
end

Più risposte (1)

Guillaume
Guillaume il 26 Gen 2017
cellfun(@transpose, yourcellarray, 'UniformOutput', false)
  6 Commenti
Guillaume
Guillaume il 27 Gen 2017
Modificato: Guillaume il 27 Gen 2017
" have a 3x1 cell matrix like this. {[1,2,3] [4,5,6] [7,8,9]}" and "I ran that, and it returned all of the elements". One of these two statements directly contradict the other:
>>c = {[1,2,3] [4,5,6] [7,8,9]};
>>find(~cellfun(@ismatrix, c))
ans =
1x0 empty double row vector
If the arrays in your cell arrays have more than two dimensions, there's no way to transpose them since transposition is only defined for 2D matrices. If what you want to do is just swap 1st and 2nd dimension, leaving the others untouced:
cellfun(@(m) permute(m, [2 1 3:ndims(m)]), yourcellarray, 'UniformOutput', false)
"Can you make a normal matrix [...] to a cell matrix" There's no such thing as a cell matrix. To produce the cell array in your example:
m = [1 2 3; 4 5 6; 7 8 9];
c = num2cell(m.', 2).'
sumana
sumana il 27 Gen 2017
Thank you for explaining the dimensions. I guess my matrix had more than two dimensions.

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