how to extract elements along specified dimension of array
58 visualizzazioni (ultimi 30 giorni)
Mostra commenti meno recenti
when e.g. selecting all elements in the 2nd dimension and the first element of all remaining dimensions of an array, for a 3-dimensional array one would write: A(1,:,1)
how to program this elegantly when the dimension over which I want the elements (2 in the example) is a variable itself, whose value is unknown until runtime ?
thanks!!
0 Commenti
Risposta accettata
Jonathan Sullivan
il 16 Mar 2012
A = rand(100,100,10,10);
dim = 4;
sz = size(A);
inds = repmat({1},1,ndims(A));
inds{dim} = 1:sz(dim);
A(inds{:})
Più risposte (2)
per isakson
il 15 Mar 2012
A(ixi,ixj,ixk)
where ixi,ixj,and ixk are numerical vectors (/scalar) of integers. ":" would correspond to (1:number_of_element_in_dimension). Or with logical indexing
A(isi,isj,isk)
where isi,isj,isk are logical vectors all with the length "number_of_element_in_dimension". ":" would be true(1,number_of_element_in_dimension).
The elegance will be in the calculation of ixi,ixj,and ixk or isi,isj,isk.
0 Commenti
Walter Roberson
il 15 Mar 2012
Something like this,
DIM = 2; %changed at runtime
idxexpr = { repmat({1}, 1, DIM - 1), {':'}, repmat({1}, 1, ndim(A)-DIM) };
A(idxexpr{:})
3 Commenti
Walter Roberson
il 15 Mar 2012
I have done it successfully before, my post is either on the newsgroup or somewhere in Answers. _Finding_ the post would take longer than reinventing it!
Try
idxexpr = [num2mat(ones(1,DIM-1)), {':'}, num2mat(ones(1,ndim(A)-DIM))];
Vedere anche
Categorie
Scopri di più su Matrix Indexing in Help Center e File Exchange
Prodotti
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!