Problem with using isfield

5 visualizzazioni (ultimi 30 giorni)
Veronika
Veronika il 6 Apr 2017
Risposto: Jan il 6 Apr 2017
Dear all,
I have one structure with 4 fields and I would like to use function isfield for other work.
I have this part of code:
if isfield(shape,'leftLung',shape,'rightLung',shape,'spine');
tmp2 = shape.spine{1};
tmp3 = shape.leftLung{1};
tmp4 = shape.rightLung{1};
and I have this error:
Error using isfield
Too many input arguments.
Error in Newmodel (line 115)
if isfield(shape,'leftLung',shape,'rightLung',shape,'spine');
Can you please advise me, how to change this part of code for good function? Thank you for your answers.
  1 Commento
Jan
Jan il 6 Apr 2017
The shown code has no valid Matlab syntax. Therefore the readers cannot know its intention. Suggesting a wrong idea might be more confusing then useful for you.

Accedi per commentare.

Risposte (2)

Thorsten
Thorsten il 6 Apr 2017
Modificato: Thorsten il 6 Apr 2017
if isfield(shape,'leftLung')
tmp3 = shape.leftLung{1};
end
if isfield(shape, 'rightLung')
tmp4 = shape.rightLung{1};
end
if isfield(shape,'spine');
tmp2 = shape.spine{1};
end
  1 Commento
Steven Lord
Steven Lord il 6 Apr 2017
You're probably going to want to add else blocks to each of those if statements, to assign default values to tmp3, tmp4, and tmp2 if the shape struct doesn't contain fields by those names.

Accedi per commentare.


Jan
Jan il 6 Apr 2017
If you have a structure with 4 fields, checking the existing of fields is not necessary. I guess:
if isfield(shape,'leftLung') && isfield(shape,'rightLung') && isfield(shape,'spine')
tmp2 = shape.spine{1};
tmp3 = shape.leftLung{1};
tmp4 = shape.rightLung{1};
end

Categorie

Scopri di più su Structures in Help Center e File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by