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why conj is used in this example?(S​can_Radar_​Using_a_Un​iform_Rect​angular_Ar​ray)

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when i learn example in matlab: Scan_Radar_Using_a_Uniform_Rectangular_Array.
I have a question,why conj is used in this code?
In order to understand this question.I have tried phased.SteeringVector and phased.PhaseShiftBeamformer function. When scan_angle is 45(deg),the pattern excited by weights obtained by these functions is showned below.At the same time, it shows that when conj is used , the main lobe is directed to -45(deg).
In this way,why conj is used in the example to detect target?(Scan_Radar_Using_a_Uniform_Rectangular_Array)

Risposte (1)

Honglei Chen
Honglei Chen il 8 Mag 2017
The confusion probably comes from the fact that the weights in radiator and pattern plot get treated slightly different.
In a beam pattern plot, the convention is to do an inner product of the steering vector and the signal vector, therefore the conjugate is automatically applied during the inner product stage.
However, in radiator, the weights are what gets directly applied to the signal. At each element, you can think of that a weight gets multiplied to the signal, it may or may not be the steering vector. so it needs a conjugate to point to the right direction.
HTH
  10 Commenti
Honglei Chen
Honglei Chen il 17 Mag 2017
This is because you passed the signal through the dechirp. If you look at the help of dechirp, it shows that the signal gets conjugated. So if you want to use dechirped signal to do the DOA estimation, you need to conjugate it again, like
xr_doa = conj(xr_doa_up);
Alternatively, you can just use the signal before the dechirp, like
[y_doa,doas] = step(hdoa,xt);
HTH

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