How do I create a large binary target matrix?

Hello. I have a dataset of 300 samples (with 60 observations each) that are divided into 6 even categories (50 samples each)

For neural networking purposes, I would like to create a target matrix such that:

0-50 = category 1
51-50 = category 2
.
.
.
251-300 = category 6

I plan to assign these values by creating a 6x300 matrix. and placing a 1 in row 1 for 0-50, a 1 in row 2 for 51-100 and so on. I believe I may be able to do this by manipulating the eye function, but I have not seen examples of this. I know there must be an easier way to do this than by logging the numbers manually... any ideas? thanks

Answer 1

[Image Analyst]

Seems kind of weird, but going precisely by your directions, 6 lines of code should do it - one line of code for the 6 groups. Can't get much simpler or easier than that. See lines of code below, following your directions which are comments:

% creating a 6x300 matrix.
m = rand(6, 300);
% placing a 1 in row 1 for 0-50, 
m(1, 1:50) = 1;
% a 1 in row 2 for 51-100,
m(2, 51:100) = 1;
% and so on
m(3, 101:150) = 1;
m(4, 151:200) = 1;
m(5, 201:250) = 1;
m(6, 251:300) = 1;

The only difference is I started at column 1 instead of 0 because there is no column 0.

[ampaul]

Thank you. This worked

Answer 2

[Walter Roberson]

Use ind2vec()

[Walter Roberson]

kron(eye(6), ones(1,50))

Answer 3

[Greg Heath]

The only way to use eye is

    target = repmat(eye(6),50)

Otherwise start with

        target = zeros(6,300)

then insert ones(1,50) into the correct locations.

Hope this helps.

Thank you for formally accepting my answer

Greg