help to fix this numeric symbolic array
Informazioni
Questa domanda è chiusa. Riaprila per modificarla o per rispondere.
Mostra commenti meno recenti
I need some help with the code below:
scaleFactors = [ 3.4, 2.3;
1.7, 1.9 ]
xMatSym = sym('X',[ 2, 2 ]);
xScaled = xMatSym./scaleFactors;
I am hoping to get the results shown below:
X1_1/3.4 X1_2/2.3
X2_1/1.7 X2_2/1.9
But, instead I am getting the results below instead:
(5*X1_1)/17 (10*X1_2)/23
(10*X2_1)/17 (10*X2_2)/19
I know the reasons it doesn't work. But I don't know how to fix this. Can someone help me?
Thank you so much!
3 Commenti
I've used the "{} code" button to format the code and the numbers. Do you see that this improves the readability? Please use this by your own in the future.
What does "fixing" mean, if the current results are correct? 5*x/17 is the same as x/3.4 mathematically. Working with integer numbers is more accurate from the view point of numerics.
I've looked at doc sym: conversion techniques, but have too few experiences with the symbolic toolbox to adjust the display as wanted.
Lisa Lee
il 12 Ago 2017
Risposte (1)
Karan Gill
il 12 Ago 2017
Modificato: Karan Gill
il 17 Ott 2017
0 voti
You can't have a "numeric symbolic" array because "numeric" and "symbolic" are different data types. For your options, see https://www.mathworks.com/help/symbolic/choose-symbolic-or-numeric-arithmetic.html.
Instead, try the vpa function on your result.
2 Commenti
Walter Roberson
il 12 Ago 2017
Note that vpa(xScaled) will get you output such as
[ 0.29411764705882352941176470588235*X1_1, 0.43478260869565217391304347826087*X1_2]
[ 0.58823529411764705882352941176471*X2_1, 0.52631578947368421052631578947368*X2_2]
You can also
>> vpa(xScaled,2)
ans =
[ 0.29*X1_1, 0.43*X1_2]
[ 0.59*X2_1, 0.53*X2_2]
Notice these are multiplications, not divisions, and it does matter for precision purposes how many digits you truncate to.
>> 1000/1.7
ans =
588.235294117647
>> 1000*.59
ans =
590
Karan Gill
il 13 Ago 2017
Yes, I do not recommend using vpa(xScaled,2) to anyone who hasn't carefully read the vpa doc :) Too much potential for confusion.
Questa domanda è chiusa.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!