Azzera filtri
Azzera filtri

For loop inside for loop

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Isma_gp
Isma_gp il 15 Ago 2017
Commentato: Adam il 15 Ago 2017
Hi, I have the following function that I am using with a single rho(1x654545) -attached. The result gives me the single peaks(1x1023). I would like to modify the script so that I can use as input rho(4x654545) and end up with the result peaks(4x1023).
Can I get some help? Thanks
x = diff(sign(rho));
indx = find(x>0);
for jj=2:length(indx);
tmp = rho(indx(jj-1):(indx(jj)));
test = dt*(indx(jj)-indx(jj-1));
peaks(jj) = max(tmp);
end
  4 Commenti
Isma_gp
Isma_gp il 15 Ago 2017
Yes, that is true. The number of values >0 could vary.
Adam
Adam il 15 Ago 2017
In that case you'd have to use a cell array or a 2d numeric array with enough rows for the case with most peaks and leave NaNs in the extra rows for the other columns.

Accedi per commentare.

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