reduce the size of figure,

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simira atraqi
simira atraqi il 17 Apr 2012
Hello Everyone, How can I reduce the size of figure in Matlab? Thanks

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Jakob Sørensen
Jakob Sørensen il 17 Apr 2012
Then you are looking for some clever matrix work, rather than figure size.
Try smth like this:
wavelength = 100;
a = 1:4001;
A = repmat(a, [3001 1]);
B = 3.*(sin((1-A).*2.*pi./wavelength)) + 1003;
figure;
imagesc(B);
Takes less than a second to run on my computer and does around the same. You might have to fix the last couple of details for it to be an exact match.

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Jakob Sørensen
Jakob Sørensen il 17 Apr 2012
Here is an example:
% Create a 1000x500 px figure, at the position x,y = 10,10 (starting at the left
% bottom corner)
superFig = figure('Position', [10 10 1000 500]);
If you want to change it for an already existing figure you just use the set function.
% Changes properties of figure named 'superFig'
set(superFig, 'Position', [10 10 1000 500]);
or
% Changes properties of current figure
set(gcf, 'Position', [10 10 1000 500]);
  4 Commenti
simira atraqi
simira atraqi il 17 Apr 2012
figure(1);
imagesc(A);
simira atraqi
simira atraqi il 17 Apr 2012
whos
Name Size Bytes Class
A 3001x4001 96056008 double array

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Jakob Sørensen
Jakob Sørensen il 17 Apr 2012
Try this:
tic;
xRes = 1; % Sets the resolution (step length), in µm, along the x-axis.
yRes = 1; % Sets the resolution (step length), in µm, along the y-axis.
zRes = 1; % Sets the resolution (step length), in µm, along the z-axis.
xLength = 4000; % Sets the length of the surface in X.
yLength = 3000; % Sets the length of the surface in Y.
wavelength = 100;
f = @(x) 3*sin(x*2*pi/wavelength) + 1003; % The function for the sine wave with the
% amplitude 3 µm and wave length of about 100 µm. Mean level is
% 1003 µm.
% Prints the sine wave into a matrix:
A = zeros(yLength/yRes+1,xLength/xRes+1);
for k = 1:length(A(:,1))
for l = 1:length(A(1,:))
A(k,l) = f(l-1);
end
end
toc;
and then...
tic;
figure(1);
imagesc(A);
toc;
You will see that the plotting part only takes around 1/50 of the total time. What is taking so long is running a loop around 12 million times.
  1 Commento
simira atraqi
simira atraqi il 17 Apr 2012
yes,
Elapsed time is 294.952000 seconds.
Elapsed time is 0.141000 seconds.
but I want to reduce the time for all the program not only for the figure.

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