How to remove repeating rows without unique function?

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I have a 624x2 matrix of ordered pairs, of which there are some repeating rows that I must remove. Is there a way to remove these repeating rows without using the unique function? Maybe using a for loop? The reason I can't use the unique function is because when I implement this matlab script in Simulink's Matlab Function block, the matrix must be sorted first before using the unique function. I can't sort the matrix because I will lose my ordered pairs and sortrows doesn't solve the issue either because I get the same error from Simulink.

Risposta accettata

Cedric
Cedric il 25 Set 2017
Modificato: Cedric il 25 Set 2017
Use the 'stable' option:
>> A = randi( 3, 10, 2 )
A =
2 3
1 1
3 1
3 1
3 1
3 3
3 3
2 1
2 3
1 1
>> unique( A, 'rows' )
ans =
1 1
2 1
2 3
3 1
3 3
>> unique( A, 'rows', 'stable' )
ans =
2 3
1 1
3 1
3 3
2 1
  8 Commenti
Andrew Poissant
Andrew Poissant il 26 Set 2017
It worked! Thank goodness. Really appreciate all of the help you gave me, you rock!
Cedric
Cedric il 26 Set 2017
My pleasure. The amount of unsupported features seems to be a real pain, good luck with the rest!

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Più risposte (1)

Jan
Jan il 26 Set 2017
Modificato: Jan il 26 Set 2017
I still do not understand, why you cannot simply sort the data. But this might be useful:
!!! UNTESTED !!!
function Data = UniqueRows2(Data)
nRow = size(Data, 1);
keep = true(nRow, 1);
for k1 = 1:nRow
if keep(k1)
for k2 = k1 + 1:nData
if keep(k2)
% For rows of length 2:
keep(k2) = (Data(k2, 1) ~= Data(k1, 1)) | (Data(k2, 2) ~= Data(k1, 2));
% General row length:
% keep(k2) = any(bsxfun(@ne, Data(k2, :), Data(k1, :)), 2);
end
end
end
end
Data = Data(keep, :);
end
This might be faster with vectorization:
function Data = UniqueRows(Data)
nRow = size(Data, 1);
keep = true(nRow, 1);
for k1 = 1:nRow
if keep(k1)
keep(k1 + 1:nData) = and(keep(k1 + 1:nData), ...
any(bsxfun(@ne, Data(k2, :), Data(k1, :)), 2));
end
end
Data = Data(keep, :);
end

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