Azzera filtri
Azzera filtri

matrix form numerical integration

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john birt
john birt il 25 Apr 2012
This code does not work
clear;
x = [1.0024 0.264 1.4334 1.46 0.0219 0.1;
1.0024 0.264 1.435 1.46 0.0220 0.1;
1.0024 0.264 1.4352 1.46 0.0221 0.1;
1.0024 0.264 1.4353 1.46 0.0222 0.1;
1.0024 0.264 1.4354 1.46 0.0222 0.1;
1.0024 0.264 1.4357 1.46 0.0223 0.1];
r = x(:,1); Y = x(:,2); q = x(:,3); K=x(:,4); L=x(:,5); c=x(:,6);
t = 0.1:0.1:0.6;
z = trapz(t,normcdf(((log(q./K)+t.*c.^2./2)./(c.*sqrt(t))),0,1));
If I just use one line of records, i.e
z = trapz(t,normcdf(((log(q(1)./K(1))+t.*c(1).^2./2)./(c(1).*sqrt(t))),0,1));
Then it works!!! What I dont understand is how to do this 'trapz' for each line of records in the vector 'x'.

Risposta accettata

Thomas
Thomas il 25 Apr 2012
you are trying to perform trapezoidal numerical integration over a number of different values but the output z is not a vector.. MAybe you need something like this.. where you get a z for each line of input data..
clear;
x = [1.0024 0.264 1.4334 1.46 0.0219 0.1;
1.0024 0.264 1.435 1.46 0.0220 0.1;
1.0024 0.264 1.4352 1.46 0.0221 0.1;
1.0024 0.264 1.4353 1.46 0.0222 0.1;
1.0024 0.264 1.4354 1.46 0.0222 0.1;
1.0024 0.264 1.4357 1.46 0.0223 0.1];
r = x(:,1); Y = x(:,2); q = x(:,3); K=x(:,4); L=x(:,5); c=x(:,6);
t = 0.1:0.1:0.6;
for i=1:length(x)
z(i) = trapz(t,normcdf(((log(q(i)./K(i))+t.*c(i).^2./2)./(c(i).*sqrt(t))),0,1));
end

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