Azzera filtri
Azzera filtri

I need to find Y values between two given points.

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I have sets of x coordinates as follows (1527 2127, 2629 3229,...etc)
I need to find the Y values between each set then take all of those values and divide it by the number of sets.
This is an ECG signal and basically, I want to make a new plot which is an average of each cycle.
  4 Commenti
the cyclist
the cyclist il 11 Nov 2017
Is x stored in a 10,000 x 2 array? Are the intervals defined by each row of x guaranteed to be disjoint from each other, with no overlap?
Inteeskimo
Inteeskimo il 11 Nov 2017
Modificato: Inteeskimo il 11 Nov 2017
yes, there is no overlap. and the x values are just time in milliseconds (0 - 10,000) and y is in millivolts. each value of x corresponds with a value of y. I could do this manually by opening the variable and copying and pasting all the values between those sets and averaging them out. the sets are the values 200 and 400 milliseconds before and after each peak respectively.

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the cyclist
the cyclist il 11 Nov 2017
Here is a small-scale example.
x = [1527 2127;
2629 3229;
4131 5555];
y = [2000;
2100;
3000;
3100;
5000];
y3 = reshape(y,1,1,[]);
intervalIndex3 = y3 > x(:,1) & y3 < x(:,2);
[intervalIndex,~,~] = ind2sub([size(x,1) 1 size(y,1)],find(intervalIndex3))
intervalIndex will tell you which row of x the value of y belongs to.

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