How to use "zeros" to replace for loop?

Hello,

I would like to use zeros to replace the for loop, I had try it before but have some errors. How to use zeros to replace for loop?

for a = 300 :2: 303;
  for b = 353 :2: 381;
    for c = 301 :2: 303;
      for d = 354 :2: 381;               
        frame1(a,b,:) = [0,0,0];
        frame1(c,d,:) = [0,0,0];
      end
    end
  end
end

Here is the loop, Thanks.

[Image Analyst]

You don't have to put semicolons at the end of the "for" lines - it doesn't have any effect.

[Jan]

"frame1(c,d,:) = 0;" is sufficient and faster than "frame1(c,d,:) = [0,0,0];". But of course Walter's solution is ways faster.

Answer 1

[Walter Roberson]

frame1(300:303, 353:381,:) = 0;

Answer 2

[Wayne King]

 frame1 = zeros(303,381,3);

[Peony Lai]

Thankyou for your answer, but the for loop is a range of coordinate, it not just 1 coordinate, and I need to make the pixel which is mentioned in the for loop to be black color, I have tried you method but didn't work, thanks.

[Wayne King]

Then I'm not sure what you're asking because my line gives the exact result of your for loop

[Walter Roberson]

Wayne, assume that frame1 is a previously-initialized array.