Azzera filtri
Azzera filtri

linspace error while trying to plot

3 visualizzazioni (ultimi 30 giorni)
Dear all,
I have written a code for linspace I want a 3D plot of it:
% First we set the constants:
kd=6;
lambda= 0.01;
Delta_E=0.02;
% Then we write down the Formulas:
z=linspace(-1,1,200);
kappa=linspace(0,1,200);
q=((Delta_E)+(lambda.*z)+(((sqrt((1+z)./2)).*exp(-(kd.*(sqrt(2.*lambda'.*(1+z))))))).*(kappa.*(sqrt((1-z)./(1+z)))-(sqrt((1+z)./(1-z )))));
% Now we plot q(Z,kappa) vs Z and kappa :
figure(1)
mesh(z,kappa,q)
% title('kd=6');
xlabel('Z');
ylabel('lambda');
zlabel('q)');
I think that my "q" must have 200*200 matrix, but it is not. Its gives just 1*200.
I would highly appreciate if you help me.
Thanks,

Risposta accettata

Walter Roberson
Walter Roberson il 30 Nov 2017
Change
z=linspace(-1,1,200);
kappa=linspace(0,1,200);
to
Z = linspace(-1,1,200);
KAPPA = linspace(0,1,200);
[z, kappa] = meshgrid(Z, KAPPA);
Note: you have
ylabel('lambda');
which is not correct. Your lambda is a constant. Your y axes is kappa, not lambda.
  2 Commenti
fartash2020
fartash2020 il 30 Nov 2017
Modificato: Walter Roberson il 30 Nov 2017
Dear Walter,
Thank you very much for your answer. Also, I want to plot Z vs kappa for the time that q=0. in 2D of course.
Best Regards,
Walter Roberson
Walter Roberson il 30 Nov 2017
contour(z, kappa, q, [0 0])
the [0 0] is a trick that has to be used when you are only asking for one contour value; if you were to try to pass in the scalar 0 at that point, it would try to interpret the scalar 0 as the number of contour levels to draw.

Accedi per commentare.

Più risposte (0)

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by