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Sorting a matrix by one column

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José Pereira
José Pereira il 7 Dic 2017
Commentato: José Pereira il 7 Dic 2017
So i have this "matrix". First column is names, second colomn is passwords. I want to display this data alphabetically by name. I don´t know how to do this.So here is the original matrix,
{'john'} {'jojo'}
{'victor'} {'vivi'}
{'andre'} {'dredre'}
and here is the result i want to display:
{'andre'} {'dredre'}
{'john'} {'jojo'}
{'victor'} {'vivi'}
Thanks!

Risposta accettata

KL
KL il 7 Dic 2017
Modificato: KL il 7 Dic 2017
That's not a matrix. If you meant to store them in cell arrays,
C = {'john', 'jojo';'victor', 'vivi';'andre', 'dredre'};
It would look like
C =
6×1 cell array
'john' 'jojo'
'victor' 'vivi'
'andre' 'dredre'
Now use just sortrows
C = sortrows(C,1)
3×2 cell array
'andre' 'dredre'
'john' 'jojo'
'victor' 'vivi'
Neverthless better idea to store such data is to use tables,
names = {'John';'victor';'andre';};
passwords= {'jojo';'vivi';'dredre'};
T = table(passwords,'RowNames',names)
and it looks like,
T =
3×1 table
passwords
_________
John 'jojo'
victor 'vivi'
andre 'dredre'
now, again sortrows,
sortrows(T)
3×1 table
passwords
_________
andre 'dredre'
John 'jojo'
victor 'vivi'
  3 Commenti
KL
KL il 7 Dic 2017
If you are still opting to use cell array, then simply use sort and only for first column. Extract the sorted indices from the result and use it sort the original cell array.
C = {'john', 'jojo';'victor', 'vivi';'andre', 'dredre'}
[~,indx] = sort(C(:,1));
sortedC = C(indx,:)
sortedC =
3×2 cell array
'andre' 'dredre'
'john' 'jojo'
'victor' 'vivi'
José Pereira
José Pereira il 7 Dic 2017
That is exactly what i wanted. Thanks

Accedi per commentare.

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