Assigning multiple variables vectors from a cell array

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I'm wondering if there is any smart solution on how to access multiple same-sized vectors inside of a cell array and assign them to an independent variable.
cellArray =
1×4 cell array
{1×101 double} {1×101 double} {1×101 double} {1×101 double}
Thanks!

Risposta accettata

Honglei Chen
Honglei Chen il 13 Dic 2017
Modificato: Honglei Chen il 13 Dic 2017
I would just do the following and then access them using 3rd indices
reshape(cell2mat(cellArray),[size(cellArray{1}) length(cellArray)])
HTH

Più risposte (2)

Adam
Adam il 13 Dic 2017
[a1, a2, a3, a4] = cellArray{:};
It is not advisable generally to do this, but for the record, that syntax should work. Having 1 variable is almost always a lot better than 4.
  2 Commenti
Johannes Berger
Johannes Berger il 13 Dic 2017
Thank you, this solution does work, although one would have to look for a way to dynamically create as much variables as needed since the number of vectors in the cell array varies.
Stephen23
Stephen23 il 14 Dic 2017
Modificato: Stephen23 il 14 Dic 2017
"...although one would have to look for a way to dynamically create as much variables as needed since the number of vectors in the cell array varies."
No, that is exactly what one should avoid doing. Magically creating or accessing variables will make your code slow, complex, buggy, obfuscated, hard to debug, and insecure. Read this to know why:
Adam already told you a much better solution, which is to keep your data in one array.

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Jan
Jan il 13 Dic 2017
Modificato: Jan il 13 Dic 2017
Do you mean:
a = cellArray{1}{1};
b = cellArray{2}{1};
c = cellArray{3}{1};
d = cellArray{4}{1};
Now a,b,c,d are 1x101 vectors.
  3 Commenti
Stephen23
Stephen23 il 14 Dic 2017
"...but this does not automatically match the varying number of vectors in the cell array."
Magically creating variables would be slow, complex, inefficient, hard to debug, and insecure. Using indexing is simple, neat, easy to debug, and very efficient.
Jan
Jan il 14 Dic 2017
Modificato: Jan il 14 Dic 2017
@Johannes: Your question looks, like you have a nested cell:
cellArray =
1×4 cell array
{1×101 double} {1×101 double} {1×101 double} {1×101 double}
Therefore I've added the {k}{1}. As Stephen has pointed out: Such an automagical creation of variables is a bad programming pattern, which is known to cause more troubles than it solves.

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