Azzera filtri
Azzera filtri

Problem in integration function containing gauss hypergeometric function

4 visualizzazioni (ultimi 30 giorni)
I am deriving the coverage probability of heterogeneous network with massive MIMO macro base station. During the process, I am stuck in the in hypergeometric function. The small part of that program is given below.
fun= @(x,y)imag(exp(pi.*1i.*(x).*y.^(-2).*hypergeom(1,[1/2,3/2],-1i.*x./(y.^4))))./x
c= @(y) integral(@(x) fun(x,y), 0.1,1,'ArrayValued',true)
fun1= @(y)((1/2)-((1/pi).*c(y))).*exp(-pi.*y.^2)
c1 = integral(fun1, 0.1,1)
I think iproblem is due to terms(y.^(-2) and and y.^4) in the fun. If any body have any idea please suggest. Any suggestions regarding this will be appreciated.
  7 Commenti
Walter Roberson
Walter Roberson il 9 Gen 2018
Modificato: Walter Roberson il 9 Gen 2018
To within the boundaries of double precision, c1 will be nan. The values involved are way way too big to work with in double precision.
Shweta Rajoria
Shweta Rajoria il 9 Gen 2018
ok sir.. thank you.. but please guide me how this problem can be resolved.

Accedi per commentare.

Risposte (1)

Walter Roberson
Walter Roberson il 8 Gen 2018
fun(8/10, 3/10) is about 2.974*10^1912918 .
fun(8/10, 2/10) is about 4.087*10^-24618734963806
fun(8/10, 0.18) is about 2.345*10^207906652598325658
So, fun is very steep, and has a lot of values that overflow floating point representation. You will not be able to integrate that using any normal representation.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by