Why ParFor does not work for this?

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Erdem Uguz
Erdem Uguz il 27 Dic 2017
Risposto: Namnendra il 19 Giu 2022
It is a really simple manipulation. I want to replace some lines of the matrix with zeros.
A=rand(20,20);
for j=1:1:4
A(4*j+1,:)=zeros;
end
When I replace for with parfor I get a classification error. But the results of the manipulation is independent from each other. I don't understand why.
Thank you Erdem

Risposte (1)

Namnendra
Namnendra il 19 Giu 2022
All variables referenced at the top level of the parfor must be resolved and classified. Go through the following link to know more :-
You can try putting the body of perfor loop into a function and calling the function from the loop.
I hope this helps.

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