Multiplication of cell arrays

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lucksBi
lucksBi il 17 Gen 2018
Commentato: lucksBi il 17 Gen 2018
hey
i have following four cell arrays(2x7 cell). i want to multiply all four. Like cell1 of a with cell 1 of b,c,d and same for all cells.
a = {[],[0.13,0.13],1.13,[0.13,0.1,1.13],[0.13,1.1,0.13],[],[]; [],[],[-1.72,-0.72,1.2],0.27,[],[0.27,1.2],[-1.7,0.2,-0.7,1.28]}
b= {[],[-0.4,-0.4],-0.2,[-0.4,-0.4,1.8],[-1.28,-1.2,0.78],[],[]; [],[],[-2.2,-1.2,0.7],0.5,[],[-0.09,-1.0],[-0.31,0.6,-2.3,1.6]}
c= {[],[1,1],1,[1,1,1],[1,1,1],[],[]; [],[],[1,1,1],1,[],[1,1],[1,1,1,1]}
d= {[],[1,1],1,[1,1,1],[1,1,1],[],[]; [],[],[1,1,1],1,[],[1,1],[1,1,1,1]}
I have used:
for x=1:2
for y=1:7
mul{x,y}=cellfun(@(x,y,z,s) x.*y.*z.*s, a{x,y},b{x,y},c{x,y},d{x,y},'UniformOutput', false);
end
end
which gives following error:
Input #2 expected to be a cell array, was double instead.
Also these arrays doesn't only contain two rows.
kindly help

Risposta accettata

Jan
Jan il 17 Gen 2018
cellfun is smart, but harder to debug than a simple loop.
mul = cell(2, 7);
for x=1:2
for y=1:7
mul{x,y} = a{x,y} .* b{x,y} .* c{x,y} .* d{x,y};
end
end
Does this work? I assume if fails with the same error. Then use the debugger:
dbstop if error
Run the code again until it stops at the error. Now check the sizes:
size(a{x,y})
size(b{x,y})
size(c{x,y})
size(d{x,y})

Più risposte (1)

Walter Roberson
Walter Roberson il 17 Gen 2018
Remove the loop.
mul = cellfun(@(x,y,z,s) x.*y.*z.*s, a, b, c, d, 'uniform', 0);
  1 Commento
lucksBi
lucksBi il 17 Gen 2018
ThankYou. It works fine of two rows but on matrix of 8x7 it gives following error:
All of the input arguments must be of the same size and shape. Previous inputs had size 1 in dimension 1. Input #3 has size 8

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