How to find the two nearest values related to a constant
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Hello to all,
I've to find what are the two values and related indices respect to a constant.
I mean as example; I've a vector and a constant like follow:
a=[1250 2320 3520 4650 5550 6760];
b= 3700;
Therefore I would receive the values 3520 and 4650 and the equivalent indices 3 e 4.
Best regards and thanks in advance.
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Risposta accettata
Thomas
il 11 Mag 2012
a=[1250 2320 3520 4650 5550 6760];
b= 3700;
% this will work even if 'a' is in random order
d=sort(abs(b-a));
lowest=find(abs(b-a)==d(1))
sec_lowest=find(abs(b-a)==d(2))
3 Commenti
Trevor Wright
il 26 Feb 2018
This doesnt work if d(1) and d(2) are equal, meaning b sits exactly halfway between two values in a. An easy way to solve this is with an if statement.
d=sort(abs(b-a));
if (d(1) == d(2))
vals = find(abs(b-a)==d(1))
lowest = vals(1)
second_lowest = vals(2)
else
lowest=find(abs(b-a)==d(1))
sec_lowest=find(abs(b-a)==d(2))
end
Nimrod
il 5 Ago 2018
Tomas, instead of using find, you can use the second output of sort, which is the index for the sorting.
Più risposte (2)
Andrei Bobrov
il 11 Mag 2012
a=[1250 2320 3520 4650 5550 6760];
b= 3700;
[~,e] = histc(b,a)
out = [a(e+(0:1)) ; e+(0:1)]
0 Commenti
Image Analyst
il 11 Mag 2012
firstIndex = find(a<b, 1, 'last')
nextIndex = firstIndex + 1
2 Commenti
Philip Bates
il 6 Mag 2016
Only works if a is consistently increasing. If a= e.g. [0, -1, -2, -3] and b = -1.4 then firstIndex = find(a<b, 1, 'last') returns -2 and nextIndex returns -3 which is not correct. You can't simply check absoloute values in case the slope reverses at some point.
Image Analyst
il 7 Mag 2016
Yes, you're right. A much better answer would have been:
a=[1250 2320 3520 4650 5550 6760]
b= 3700
differences = abs(a-b)
[minDiff, indexOfMinDiff] = min(differences);
closestValue = a(indexOfMinDiff);
message = sprintf('The value in "a" closest to "b" is %d', closestValue);
uiwait(helpdlg(message));
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