Azzera filtri
Azzera filtri

vector

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lowcalorie
lowcalorie il 12 Mag 2012
i have a vector
X = [.00000;.00001;.00002;.00003;.00004;.00005;.00006;.00007;.00008;.00009;];
i need to do X/(X-1) value not 1 the number
(x-1) needs to equal a value to the left of X
example .00002/.00001
  1 Commento
Image Analyst
Image Analyst il 12 Mag 2012
Realize that X(2)/X(1) will work but its value will be inf (infinity).

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Risposte (1)

Oleg Komarov
Oleg Komarov il 12 Mag 2012
Manually:
X(2:end)./X(1:end-1)

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