comparing elements of a cell array based on another cell array

hi

    array1 = {[2,5];[1,3,4]}
    array2= {[1,4],[1,5],5,4,[3,5,2]}

I need to perform a comparison. 1st element of array1 is [2,5] which is at position 1 in array1. so it will take 1st value in array2 [1,4] and compare it with 2nd and 5th value in array2 which are [1,5] and [3,5,2]. and in result it will take out the one which has at least one value in common with [1,4] as here we will get 2 because 2nd element [1,5] has '1' common with [1,4].

for 2nd element in array1 which is [1,3,4], it will take 2nd value of array2 and compare it with 1st,3rd and 4th value and [1,3] will be in result because 4th value which is [4] has nothing in common with [1,5].

so output will be:

    ResultantantArray = {2,[1,3]}

i hope i have explained it well. kindly help on this.

Thanks in anticipation

[Jos (10584)]

What did you try yourself in pseudocode, using loops, for instance? Also see

help intersect

Answer 1

[Andrei Bobrov]

a1 = {[2,5];[1,3,4]};
a2= {[1,4],[1,5],5,4,[3,5,2]};

n = numel(a1);
out = cell(n,1);
nn = cellfun(@numel,a2);
for ii = 1:n
    jj = a1{ii};
    t = repelem(jj,nn(jj));
    out{ii} = unique(t(ismember([a2{jj}],a2{ii})));
end

[lucksBi]

Thanks a bunch for solution.

One problem i face is that it gives repetitive values in result. Like if i run it on following array:

a1=  {[2,5];[1,3,4,5,6,8]}
a2= {[7,8],[3,9],5,9,[3,5,8],7,[],[3,5,9]}
ResultantArray = {5;[4,5,8,8]} % where 5 is fine but in [4,5,8,8], 8 appears 2 time

[Andrei Bobrov]

I'm fixed my answer.

[lucksBi]

yup i added 'unique'... Thanks alot.