iteration chaotique

1 visualizzazione (ultimi 30 giorni)
slama najla
slama najla il 19 Mag 2012
hello i need a matlab code that can be able to give me us output positiv intgers from that are included in[1,128] for X and Y but [1,28] for Z , i have this chaotic code but i can't arrive to put a candition that give positiv integers from this intervals:
X=8; K=50; % X: la clé, K: Nombre d’itérations
for i=1:K
X=4*X*(1-X); % itération de la Carte logistique
Y=4*X*(1-X);
Z=4*Y*(1-Y);
end
Please help me if you can.Thanks

Risposta accettata

per isakson
per isakson il 21 Mag 2012
Run this function with start value for X in the interval (0,1).
function cssm()
X=0.5325; K=100; % X: la clé, K: Nombre d’itérations
figure
plot3( 1, 1, 1 )
hold on
plot3( -1, -1, -1 )
for i=1:K
X=4*X*(1-X); % itération de la Carte logistique
Y=4*X*(1-X);
Z=4*Y*(1-Y);
% fprintf( '%15f%15f%15f\n', X, Y, Z )
plot3( X, Y, Z, 'd' )
pause( 0.02 )
end
end

Più risposte (1)

Walter Roberson
Walter Roberson il 21 Mag 2012
If X and Y are currently positive integers, then under what circumstances can X or Y stop being a positive integer in the code?
If X is a currently a positive integer but Y is not a positive integer, then under what circumstances would X continue to be a positive integer and Y would become a positive integer? Likewise for X not currently positive integer but Y being positive integer.
If neither X nor Y are currently positive integer, then under what circumstances can both become positive integers?
Once you have gone through that analysis, you should be in shape for figuring out the circumstances under which X, Y and Z all become positive integers.
  1 Commento
per isakson
per isakson il 21 Mag 2012
zero is that an interger? What about the "spring break"?

Accedi per commentare.

Categorie

Scopri di più su Food Sciences in Help Center e File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by