Error: Assignment has more non-singleton rhs dimensions than non-singleton subscripts

1 visualizzazione (ultimi 30 giorni)
Hello, I'm fairly new to MATLAB and I am unsure as to why my code came up with this error. This was part of the error message:
Assignment has more non-singleton rhs dimensions than non-singleton subscripts
Error in evalcontrol (line 9)
u(:,ii)=-sys.r\sys.b'*reshape(deval(solp,Tf-t),length(x),length(x))*x;
Error in ACS420_3 (line 37)
[u,J,Jf]=evalcontrol(tspan,sys_name,solx,solp,Tf);
My parameters are as follows, and are in a function called imresp.m:
function sys=imresp(t,x)
a11=1; a12=1; a23=1; a31=1; a42=1; b2=1; b3=1;
b1=-1; b4=-1;
a22=3;
a32=1.5;
a33=0.5; a41=0.5;
f11=1; f44=1; q11=1; q44=1; r11=1; r22=1;
x2bar=2; x3bar=a31*x2bar/a32;
if nargin==0; sys.f = [f11 0 0 0; 0 0 0 0; 0 0 0 0; 0 0 0 f44]; sys.xe = [0 x2bar x3bar 0]';
else
sys.a = [((a11-a12*x3bar)-a12*x(3)) 0 0 0;...
a21(x(4))*a22*(x(3)+x3bar) -a23 0 0;...
-a33*x3bar a31 -(a32+a33*x(1)) 0;...
a41 0 0 -a42];
sys.b = [b1 0 0 0; 0 b2 0 0]';
sys.q = [q11 0 0 0; 0 0 0 0; 0 0 0 0; 0 0 0 q44];
sys.r = [r11 0; 0 r22];
end
and evalcontrol.m is:
function [u,J,Jf]=evalcontrol(tspan,sys_name,solx,solp,Tf)
xf=deval(solx,Tf);
tmp=zeros(1,length(tspan));
u=zeros(1,length(tspan));
for ii=1:length(tspan)
t=tspan(ii);
x=deval(solx,t);
sys=feval(sys_name,t,x);
u(:,ii)=-sys.r\sys.b'*reshape(deval(solp,Tf-t),length(x),length(x))*x;
tmp(ii)=x'*sys.q*x+u(:,ii)'*sys.r*u(:,ii);
end
J=cumtrapz(tspan,tmp)/2; % cumtrapz - cumulative trapezoidal numerical integration
sys=imresp2;
Jf=0.5*xf'*sys.f*xf;
Help is much appreciated. Thank you!
  6 Commenti
chromaclouds
chromaclouds il 23 Apr 2018
Modificato: chromaclouds il 23 Apr 2018
oops sorry, imresp2 is imresp. I forgot to change the name of the file. everything that is 'imresp2' is actually 'imresp' (in evalcontrol and ACS420_3).

Accedi per commentare.

Risposta accettata

Walter Roberson
Walter Roberson il 23 Apr 2018
In imresp you have
sys.b = [b1 0 0 0; 0 b2 0 0]';
that forces sys.b to be 4 x 2. When you work with in in evalcontrol in
u(:,ii)=-sys.r\sys.b'*reshape(deval(solp,Tf-t),length(x),length(x))*x;
then that forces there to be two rows of output. The various 1 x 4 and 4 x 4 cancel out effectively to make the number of columns of sys.b the control over the number of rows of result.
So the right hand side ends up being 1 x 2, being stored into column #ii of u. And that is a problem because you initialized
u=zeros(1,length(tspan));
so u only has one row, but you are trying to store two rows.
If you just change to
u=zeros(2,length(tspan));
then the code will proceed on to some plots.

Più risposte (0)

Categorie

Scopri di più su Model Predictive Control Toolbox in Help Center e File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by