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How do I repeat a for loop for all columns?

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I have a for loop that runs through all of my 1,000 rows. The next step is to get this code to run exactly the same way but for each of the 10,000 columns. I don't know if there is a simple way to do this--I tried adding "for j=1:n_trials" but that didn't seem to work. Any help is appreciated. Thanks!
n_steps = 1000 n_trials = 10,000 x_pos = zeros(n_steps,n_trials);
for i=2:n_steps
direction=rand;
if direction < 0.3
x_pos(i) = x_pos(i-1)+1;
elseif (0.3 < direction) && (direction < 0.5)
x_pos(i)=x_pos(i-1)-1;
else
x_pos(i)=x_pos(i-1);
end
end

Risposta accettata

Akbar
Akbar il 7 Mag 2018
Modificato: Akbar il 7 Mag 2018
Try this. You should use two arguments (i,j) i=row number. j=column number. And one more "for" Loop, for the columns.
n_steps = 1000;
n_trials = 10000;
x_pos = zeros(n_steps,n_trials);
for i=2:n_steps
for j = 1:n_trials
direction=rand;
if direction < 0.3
x_pos(i,j) = x_pos(i-1,j)+1;
elseif (0.3 < direction) && (direction < 0.5)
x_pos(i,j)=x_pos(i-1,j)-1;
else
x_pos(i,j)=x_pos(i-1,j);
end
end
end

Più risposte (1)

Jan
Jan il 7 Mag 2018
With a vectorized approach:
n_steps = 1000;
n_trials = 10000;
x_pos = zeros(n_steps, n_trials);
for k = 2:n_steps
direction = rand(1, n_trials);
step = zeros(1, n_trials);
step(direction <= 0.3) = 1;
step((0.3 < direction) && (direction < 0.5)) = -1;
x_pos(k, :) = x_pos(k-1, :) + step;
end
I've modified one condition from < 0.3 to <= 0.3, such that direction==0.3 is caught also.

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