How to take the 8th bit in lsb

I am applying LSB for image steganography and I have got the binary representation of an rgb image i. e. 10001010 but I m not getting any idea of how to use the 8th bit to hide data in it anybody plz help me.

[Shrestha Kumar]

Hi,

If you are here to know about steganography then this article will help you

https://null-byte.wonderhowto.com/how-to/steganography-hide-secret-data-inside-image-audio-file-seconds-0180936/

[Jan]

The readers cannot guess, what "binary representation of an rgb image i. e. 10001010" exactly is. Is this a logical vector, a decimal number or a character vector? Did you search in the forum for "lsb steganography" already? You will find a lot of corresponding threads.

I strongly recommend to remove the "ASAP" from the question. Pushing the readers is counterproductive, because it sounds impolite.

[Swati Nagpal]

the binary representation of 10001010 is just an example from my side. The thing is i have got uptothe binary representation of the image and now i have to take the 8th least bit of it to apply the lsb technique. i want a code for it so please help me in this.

Answer 1

[Walter Roberson]

You can use bitset() and bitget() .

To extract the lsb you can use mod(YourImage,2) . To set new lsb you can do

YourImage - mod(YourImage,2) + NewLSBValue