How to find "maximum" value in a table

117 visualizzazioni (ultimi 30 giorni)
How to find "maximum" value in a table and to extract the other data's based on maximum value (i.e maximum value row):
I have a table with 6 columns as shown below
Calcul = table;
Calcul.Element = cell2mat(raw(:, 1));
Calcul.Tau = cell2mat(raw(:, 2));
Calcul.Pressure = cell2mat(raw(:, 3));
Calcul.VMStress = cell2mat(raw(:, 4));
Calcul.SPmax = cell2mat(raw(:, 5));
Calcul.SPmin = cell2mat(raw(:, 6));
I need to find a maximum value/cell of a particular column and to extract all the data from these 6 columns (i.e row of a particular cell) as attached in the image.
Please help me
Thanks in advance
  4 Commenti
Lal
Lal il 5 Giu 2018
Modificato: Lal il 5 Giu 2018
VM_max = max(Calcul.VMStress);
VM_max
This is giving maximum of 4th column. How do I extract the row (VM_max) ?
Thanks in advance
Peter Perkins
Peter Perkins il 7 Giu 2018
Stephen's comment was just that you have six lines to create six table variables, and because each of those six references a column in the same cell array, you could replace all those with one call to cell2table.

Accedi per commentare.

Risposta accettata

Razvan Carbunescu
Razvan Carbunescu il 5 Giu 2018
Can accomplish this easier with indexing
>> T = readtable('test1.txt');
>> [~,maxidx] = max(T.SPmin);
>> T(maxidx,:)
ans =
1×6 table
Element Tau Pressure VMStress SPmax SPmin
_______ ______ ________ ________ ______ ______
54281 2.5304 -3.6719 4.479 6.5101 1.4493
  2 Commenti
Lal
Lal il 5 Giu 2018
Modificato: Lal il 5 Giu 2018
Thank you for your answer. Could you please explain me how the code is working?
Thank you
Razvan Carbunescu
Razvan Carbunescu il 5 Giu 2018
The second line computes the max of T.SPMin and stores the position where that max is found in maxidx. Then via table indexing on the 3rd line can find the result.

Accedi per commentare.

Più risposte (0)

Categorie

Scopri di più su Cell Arrays in Help Center e File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by