random

4 visualizzazioni (ultimi 30 giorni)
Niki
Niki il 6 Giu 2012
I have a Matrix as follows
x = [1 2 3 4 5
6 7 8 9 10
11 12 13 14 15
16 17 18 19 20];
I want to generate a matrix from it that will be for example 100 combination of each element but for example for the first iteration, from first colum only one of them select then from the second as well then from the third as well and untill the end
so I may have like this
x = [ 6 2 18 4 20
16 17 3 4 10
and so on

Risposta accettata

Andrei Bobrov
Andrei Bobrov il 6 Giu 2012
x = [1 2 3 4 5
6 7 8 9 10
11 12 13 14 15
16 17 18 19 20];
EDIT after Mohammad's coment
[m,n] = size(x);
df = bsxfun(@plus,fullfact(m*ones(1,n)),(0:n-1)*m);
k = randperm(size(df,1));
out = x(df(k(1:min(100,numel(k))),:));
OR
[m,n] = size(x);
xc = mat2cell(x,m,ones(n,1));
cc = cell(1,n);
[cc{:}] = ndgrid(xc{:});
k = randperm(numel(cc{1}));
out = cell2mat(cellfun(@(x)x(k(1:min(100,numel(k)))'),cc,'un',0));
  3 Commenti
Niki
Niki il 6 Giu 2012
I want to have something lets say, number of permutation , can you also tell me what should I do with that?
for example I want to have only 100 generated row
more or less
Andrei Bobrov
Andrei Bobrov il 6 Giu 2012
full number of permutation for matricies with size m x n : N = m^n

Accedi per commentare.

Più risposte (0)

Categorie

Scopri di più su Creating and Concatenating Matrices in Help Center e File Exchange

Tag

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by