WHAT'S THE ALGORITH APPROACH FOR THE BELOW CODE?

clc;
clear all;
Photo='Resistor (1M).png';  %Resistor image path
RGB=imread(Photo);
matrixSize=size(RGB);
Y=matrixSize(1,1);
X=matrixSize(1,2);
x1 = Y;
Y=Y/2;
Y=round(Y);

for i=1:x1
    for t=1:X
        if RGB(i,t)<255
            Mask(i,t)=0;
        else
            Mask(i,t)=255;
        end
    end
end
figure, imshow(Mask)

for i=1:X
    if RGB(Y,i)==0 && RGB(Y,i,2)==0 && RGB(Y,i,3)==0
        Temp(i,1)='A';
    else
        Temp(i,1)=0;
    end
end

for i=1:X
    if RGB(Y,i)>=185 && RGB(Y,i,2)>=122 && RGB(Y,i,3)<=87
        Temp(i,1)='B';
    end
end

for i=1:X
    if RGB(Y,i)>=200 && RGB(Y,i,2)<=50 && RGB(Y,i,3)<=50
        Temp(i,1)='R';
    end
end

for i=1:X
    if RGB(Y,i)>=240 && RGB(Y,i,2)>=230 && RGB(Y,i,3)<=10
        Temp(i,1)='Y';
    end
end

for i=1:X
    if RGB(Y,i)<=140 && RGB(Y,i,2)<=140 && RGB(Y,i,3)>=200
        Temp(i,1)='D';
    end
end

for i=1:X
    if RGB(Y,i)==163 && RGB(Y,i,2)==73 &&RGB(Y,i,3)==164
        Temp(i,1)='V';
    end
end

for i=1:X
    if RGB(Y,i)==0 && RGB(Y,i,2)==255 &&RGB(Y,i,3)==0
        Temp(i,1)='G';
    end
end

j=1;
i1=0;
for i=1:X
    if Temp(i,1)~=0
        colorArray(1,j)=Temp(i,1);
        j=j+1;
        i1=i1+1;
    end
end

i1=floor(i1/3);
i2=floor(i1*2);
i3=floor(i2+i1);

j=1;
for i=1:X
    if Temp(i,1)~=0
        colorArray(1,j)=Temp(i,1);
        j=j+1;
    end
end

colorArray(1,1)= colorArray(1,floor(j/6));
colorArray(1,2)= colorArray(1,floor(j/3)+1);
colorArray(1,3)= colorArray(1,floor(j-2));

i=1;
for i=1:3
    if colorArray(1,i)==65      %black
        colorArray(1,i)=0;
    end

      if colorArray(1,i)==66      %brown
          colorArray(1,i)=1;
      end  

      if colorArray(1,i)==82      %red
          colorArray(1,i)=2;
      end

      if colorArray(1,i)==79      %orange
          colorArray(1,i)=3;
      end

      if colorArray(1,i)==89      %yellow
          colorArray(1,i)=4;
      end

      if colorArray(1,i)==71      %green
          colorArray(1,i)=5;
      end

      if colorArray(1,i)==68      %blue
          colorArray(1,i)=6;
      end

      if colorArray(1,i)==86      %violet
          colorArray(1,i)=7;
      end

      if colorArray(1,i)==72      %grey
          colorArray(1,i)=8;
      end

      if colorArray(1,i)==87      %white
          colorArray(1,i)=9;
      end
  end

       hundreds=power(10,colorArray(1,3));
       tens=colorArray(1,1)*10;
       ones=colorArray(1,2)*1;

       resistorValue=(tens+ones)*hundreds;

       if resistorValue>=1000 && resistorValue<1000000
           resistorValue=resistorValue/1000;
           fprintf('Resistor Value: %dk ohm',resistorValue);
       elseif resistorValue>=1000000
           resistorValue=resistorValue/1000000;
           fprintf('Resistor Value: %dM ohm',resistorValue);
       else
           resistorValue=(tens+ones)*hundreds;
           fprintf('Resistor Value: %d ohm',resistorValue);
       end
  figure, imshow(Photo);

[Adam]

https://uk.mathworks.com/matlabcentral/answers/13205-tutorial-how-to-format-your-question-with-markup#answer_18099

What exactly are you asking? You just pasted in a load of (very ugly) code with no comment or question to go with it apart from the vague one in the title. It's useful to know where code comes from if you are expecting people to try to make sense of it and explain it. Arbitrary 3rd party code may be total junk that has no sense to it so it is a waste of time trying to make sense of it without having some kind of background as to where it comes from and what its supposed purpose is.

[Guillaume]

Arbitrary 3rd party code may be total junk

Exhibit A in the question!

The code scans through the image no less than 8 times. One of these, in order to create a mask that is never used. There's more nonsense later on where things are repeated for no reason and calculations are performed and never used. And in the end the code takes into account the value of only 3 pixels.

Then, we have the nonsense that is X is the number of columns, but x1 (which used to be Y) the number of rows (and Y is now half the number of row). How can anybody keep track of what each variable represent is beyond me.

Not one of the loop is needed. The code is indeed complete junk and should be thrown away.

Answer 1

[Jan]

The code classifies the RGB colors of pixels, most likely to identify the color codes on a resistor.

The code is poorly comments and therefore it cannot work reliably - at least its purpose can be guessed only. I would not use such code for serious work.

In addition is is poorly written. Example:

for i=1:x1
  for t=1:X
      if RGB(i,t)<255
          Mask(i,t)=0;
      else
          Mask(i,t)=255;
      end
  end
end

can be improved:

Mask = (RGB(1:x1, 1:X) == 255) * 255

[Guillaume]

x1 is the height of the image, X is the width (sic!), so even simpler:

Mask = 255 * (RGB(:, :, 1) == 255);

However, since Mask is never used the whole thing is pointless.

The code classifies the RGB colors of pixels, most likely to identify the color codes on a resistor

It will only work on an ideal image of a resistor where black is exactly pure black (RGB [0,0,0]) green is exactly pure green (RGB [0, 255, 0]) and violet is exactly RGB [163, 73, 164]. I'd like to see a photo of a resistor where this is indeed the case.

Answer 2

[vv_art]

here is the image of the resistor hich had no tolerance band.This code is only for this kind of images. I am new to this.sorry for posting unclearly. Thanks for your quick response.

[Image Analyst]

The code may work for that pure computer graphics image but won't work in general. I agree with the others that the code was written by a complete amateur and you should run fast and far from it. There are other resistor postings here which may have better code (not sure) so you might search for them.

[vv_art]

Please help me sir.

[Guillaume]

It's unclear what you need help with here

Answer 3

[vv_art]

Please Help me how to approach for finding the colour bands in the resistor image or suggest any alternatative mathod for colour detection of bands in the image