Azzera filtri
Azzera filtri

What does this error mean?

1 visualizzazione (ultimi 30 giorni)
Evan Mossel
Evan Mossel il 23 Lug 2018
Modificato: Evan Mossel il 26 Lug 2018
I keep getting the error: Subscript indices must either be real positive integers or logicals.
days=10;
dy=-1;
hPlot1 = plot(dy,alt);
while dy<=days
%--calculate & display current time (UTC)
yr=2018;
mnth=1;
dy=dy+1;
hr=0;
min=0;
sc=0;
d=datetime(yr,mnth,dy,hr,min,sc);
%d=datetime('now');
%--covert and display current time in julian days
JD_TT=juliandate(d);
%--convert julian days to moon position
CooType='q2000';
[X,Y,Z]=moonpos(JD_TT,CooType);
%plot3(X,Y,Z);
%--convert to LLA coordinates, in degrees
alt=sqrt(X.^2+Y.^2+Z.^2);
xdata = get(hPlot1,'XData');
ydata = get(hPlot1,'YData');
set(hPlot1,'XData',[xdata dy],'YData',[ydata alt]);
end
altmax=max(ydata);
xmax=find(alt==altmax);
altmin=min(ydata);
xmin=find(alt==altmin);
  15 Commenti
Walter Roberson
Walter Roberson il 24 Lug 2018
Your xdata and ydata is going to include that initial nan value.
At the end of your loop, your xdata and ydata are not going to include the last dy and alt, because you change hPolt1's XData and YData after you assign to the temporary variable xdata and ydata.
Evan Mossel
Evan Mossel il 26 Lug 2018
Modificato: Evan Mossel il 26 Lug 2018
I changed the xdata/ydata to Xdata/Ydata but this did not resolve the issue.
Update: I misunderstood. This fixed the issue

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Risposte (1)

Krithika A
Krithika A il 24 Lug 2018
You use min in your code. min is already a matlab function
  5 Commenti
Krithika A
Krithika A il 24 Lug 2018
Not specifically for min/max. Min/max can handle non-integers. It would be another function.
Evan Mossel
Evan Mossel il 24 Lug 2018
I believe it is the 'find' function. I will try to work it out.

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