How can I perform 'Hierarchical Clustering' by Absolute value of correlation?

2 visualizzazioni (ultimi 30 giorni)
I'm trying to do hierarchical clustering in MATLAB using 'linkage' and 'pdist' functions. I'm familiar with the functions, but I'm attempting to cluster by the absolute value of the correlation values.
The default for the 'pdist' function, 'correlation', would include both the positive and negatives, but I'm interested in grouping inverse relationships as well.
Does anyone know how I can achieve this?

Risposta accettata

MathWorks Support Team
MathWorks Support Team il 17 Lug 2018
There are two ways in which this can be done:
First, notice that 'pdist' computes one minus the correlations among rows:
>> x
x =
1 2 3 4
2 3 2 3
1 2 3 4
4 3 2 1
>> pdist(x,'cor')
ans =
0.5528 0 2.0000 0.5528 1.4472 2.0000
>> 1-corr(x')
ans =
0 0.5528 0 2.0000
0.5528 0 0.5528 1.4472
0 0.5528 0 2.0000
2.0000 1.4472 2.0000 0
1) The first way is to compute the distance as one minus the absolute correlation, and compute linkage based on that.
>> D = pdist(x,'cor');
>> linkage(D,'single')
ans =
1.0000 3.0000 0
2.0000 5.0000 0.5528
4.0000 6.0000 1.4472
>> C = 1-D % get correlation
C =
0.4472 1.0000 -1.0000 0.4472 -0.4472 -1.0000
>> D = 1-abs(C) % get 1-abs(correlation)
D =
0.5528 0 0 0.5528 0.5528 0
>> linkage(D,'single') % cluster using that
ans =
3.0000 4.0000 0
1.0000 5.0000 0
2.0000 6.0000 0.5528
Notice that points 1,3,4 are clustered with zero distance, even though the correlation with the point 4 is '-1'.
2) The second way is to write the distance into the 'linkage' command:
>> linkage(x,'single',@(xrow,ymat) 1-abs(corr(xrow',ymat')))
ans =
3.0000 4.0000 0
1.0000 5.0000 0
2.0000 6.0000 0.5528

Più risposte (0)

Tag

Non è stata ancora inserito alcun tag.

Prodotti


Release

R2017b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by