breaking a column of strings in two different columns

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Dear all,
Inside the workspace I have the following column in cell format
Column 1
AR021108'
'AW301108'
'EW281208'
'RT250109'
'RY220209'
I was trying to break this column in two other where the first column will contain the first two elements of each of these string variables and the second one will contain the dates as follows
Column1 column 2
AR 02/11/08
AW 30/11/08
EW 28/12/08
RT 25/01/09
RY 22/02/09
Any suggestions?
  1 Commento
antonet
antonet il 19 Giu 2012
I used strtok(jji,'0 1 2 3 6 7 8 9'); wherre jji is the name of the column and i managed to create the first colum. The second column has the form
021108
301108
281208
250109
220209
but my goal is to have
02/11/08
30/11/08
28/12/08
and so forh. Thank you

Accedi per commentare.

Risposta accettata

Kevin Holst
Kevin Holst il 19 Giu 2012
It appears that you can't really do matrix operations on cell arrays like:
mycell{:,2} = mycell{:,1}(3:end);
So here's what I've got for you. It's probably not the most elegant solution, but it works...
for i = 1:length(mycell)
mycell{i,2} = [mycell{i,1}(3:4) '/' mycell{i,1}(5:6) '/' mycell{i,1}(7:8)];
mycell{i,1} = mycell{i,1}(1:2);
end

Più risposte (1)

Thomas
Thomas il 19 Giu 2012
a={'AR021108'
'AW301108'
'EW281208'
'RT250109'
'RY220209'};
ii=cellfun(@(x) x(1:2),a, 'UniformOutput', false);
jj=cellfun(@(x) [x(3:4) '/' x(5:6) '/' x(7:8)], a, 'UniformOutput', false);
out=[ii jj]
another way without loops..

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