Changing the size of Vector (n no. of zeros to one zero and n no. of ones to 1)

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Hi all, I have a vector A and i need to convert it into B. How can i do that with coding? The last value is the only exception in terms of size;
zer= zeros(1,20);
on= ones(1,20);
A=[zer zer on on zer on zer on zeros(1,10)];
B=[0 0 1 1 0 1 0 1 0];
If found zeros put one zero in vector B and if ones then 1 in vector B

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Rik
Rik il 21 Ago 2018
Modificato: Rik il 21 Ago 2018
This code should work to remove duplicate values.
A=[1 1 0 0 1 1 1 0 1 0 1];
%A=randi([0 1],1,100);
d=[false diff(A)==0];
A(d)=[];
old code:
If your input follows this pattern strictly, you can just use indexing to get the values:
zer= zeros(1,20);
on= ones(1,20);
A=[zer zer on on zer on zer on zeros(1,10)];
B=[0 0 1 1 0 1 0 1 0];
B2=A(1:20:end);
isequal(B,B2)
  6 Commenti
Rik
Rik il 21 Ago 2018
Then B2=A(1:20:end); will work. It selects the first from every 20 elements in your vector, so it condenses your 1120 element vector down to 56 elements. Then call to end in that indexing takes care of any larger vector.
ARN
ARN il 12 Set 2018
Hi, Hope u can help again
A1= [- - - - - - - - - 15:30:00 15:30:01 15:30:02 15:30:03 15:30:04 15:30:05 15:30:06 15:30:07 - - - - 15:30:12 15:30:13 15:30:14 15:30:15 15:30:16 15:30:17 - - - - - - 15:30:24 15:30:25 15:30:26 15:30:27 - - 15:30:30 15:30:31 - - ];
How can i get B1 from A1 . A1 is random will change everytime
B1= [0 15:30:00 15:30:07 0 15:30:12 15:30:17 0 15:30:24 15:30:27 0 15:30:30 15:30:31 0];
Thanks, Link to the question: https://www.mathworks.com/matlabcentral/answers/418675-getting-the-indices-of-an-array-with-conditions

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