how to do a subplot loop?

Hi, I'm trying to subplot whithin a for loop. I'm asking matlab tu plot me three contourf called nzero_mean1, nzro_mean2, nzro_mean3 in a single subplot and each countourf has a title. But I don't know how to make those trhee contourf at one subplot in a forloop. I need help. I'm currently doing it like this:

figure
subplot(1,3,1)
contourf(nzro_frec1)
set(gca,'XTickLabel',vec)
set(gca,'YTickLabel',vec)
title('Especie 1')
colorbar('southoutside')

subplot(1,3,2)
contourf(nzro_frec2)
set(gca,'XTickLabel',vec)
set(gca,'YTickLabel',vec)
title('Especie 2')
colorbar('southoutside')

subplot (1,3,3)
contourf(nzro_frec3)
set(gca,'XTickLabel',vec)
set(gca,'YTickLabel',vec)
title('Especie 3')
colorbar('southoutside')

[ax1,h1]=suplabel('Delta m3');
[ax2,h2]=suplabel('Delta m2','y');
[ax3,h3]=suplabel('Frecuencia de sobrevivencia. Alpha = 0. p=10. Respuesta Sigmoide (s=2)'  ,'t');
set(h3,'FontSize',20)
set(h1,'FontSize',14)
set(h2,'FontSize',14)

orient portrait
print('-dps','suplabel_test')
%unix('convert suplabel_test.ps suplabel_test.jpg');

Answer 1

[Image Analyst]

It wouldn't be worth it. You'd have to have if blocks in the loop to handle cases that should be different on every loop but don't depend on the loop iterator. Sure you could do

for k = 1 : 3
    subplot(1, 3, k);
    % code
    caption = sprintf('Especie %d', k);
    title(caption);
end

but the contourf, etc. are not a function of k so you'd have to say

if k == 1
    contourf(nzro_frec1)
    colorbar('southoutside')
elseif k == 2
    contourf(nzro_frec2)
    colorbar('southoutside')

etc. that essentially the looping is not gaining you anything.

[Beatriz Sanchez]

Thank yo very much, well I end up doing it like this:

   for i=1:3
       figure(1)
subplot(1,3,i)
if i==1
contourf(nzro_mean1)
elseif i==2
    contourf(nzro_mean2)
elseif i==3
    contourf(nzro_mean3)
end
axis square
set(gca,'XTickLabel',vec)
set(gca,'YTickLabel',vec)
title(['Especie ',num2str(i)])
colorbar('southoutside')

   end

I think it's better that what I had.