How to make inline function using for loop?
4 visualizzazioni (ultimi 30 giorni)
Mostra commenti meno recenti
Sajjad Malik
il 22 Set 2018
Commentato: Sajjad Malik
il 23 Set 2018
I need to make following function using "function handle"....
x=[x(1),x(2),x(3),...…,x(N)]……..Let say N=50
for i=1:1:N
fun(i)=@(x) 2*a + b + 4*c*d + 6*e %a, b ,c , d and e are iterative variables
end
a=[x(1),x(6),x(11),x(16),x(21),x(26),....,x(46)]
b=[x(2),x(7),x(12),x(17),x(22),x(27),.....x(47)]
c=[x(3),x(8),x(13),x(18),x(23),x(28),.....x(48)]
d=[x(4),x(9),x(14),x(19),x(24),x(29),.....x(49)]
e=[x(5),x(10),x(15),x(20),x(25),x(30),.....x(50)]
How can I write function using for loop?
2 Commenti
Risposta accettata
Walter Roberson
il 22 Set 2018
fun = cell(N, 1);
F = @(x) 2*x(1:5:N) + x(2:5:N) + 4*x(3:5:N).*x(4:5:N) + 6*x(5:5:N);
fun(:) = {F};
Now fun stores N copies of the same function handle, each of which implements
@(x) 2*a + b + 4*c*d + 6*e
where a, b, c, d, e are short-hand for
a=[x(1),x(6),x(11),x(16),x(21),x(26),....,x(46)]
b=[x(2),x(7),x(12),x(17),x(22),x(27),.....x(47)]
c=[x(3),x(8),x(13),x(18),x(23),x(28),.....x(48)]
d=[x(4),x(9),x(14),x(19),x(24),x(29),.....x(49)]
e=[x(5),x(10),x(15),x(20),x(25),x(30),.....x(50)]
Each of the function handles will return a vector of length 50/5 = 10.
5 Commenti
Walter Roberson
il 23 Set 2018
No. When your objective function returns a vector of results, then fmincon and most other minimizers are not appropriate. You would need something like gamultiobj() which tries to find pareto fronts.
Più risposte (0)
Vedere anche
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!