c file name from grt generated code
6 visualizzazioni (ultimi 30 giorni)
Mostra commenti meno recenti
Chirag Jagadish
il 26 Set 2018
Commentato: Chirag Jagadish
il 11 Gen 2019
I have a tlc file which accesses the c file name generated through grt.tlc
%assign modelFileName = LibGetSourceFileSection(fileIdx, "Name")
Some times without any reason, the above code returns the complete path of the file and at most times only the name of the c or header file.
How can i filter out the complete path details and get only the file name from the string that is returned above?
Example Most of the time, modelFileName is populated as file name.c or file name.h Some times, it comes back as D:\MyGenFiles\StorageLoc\_sharedutils\<c file name>.c
How do i remove the "D:\MyGenFiles\StorageLoc\_sharedutils\" part from the string above in tlc.
I have to do this only in the tlc environment.
Risposta accettata
Mark McBroom
il 11 Gen 2019
Probably the easiest approach is to write a simple MATLAB function that takes as an argument the modelFileName, then uses fileparts() to strip off the directory name and returns the file name. Then call this MATLAB function from TLC using the built-in TLC function FEVAL().
Più risposte (0)
Vedere anche
Categorie
Scopri di più su Simulink Coder in Help Center e File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!