Problem using function handles
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I have a homework problem where I have to code a function for a bisection root finder. One of the inputs to the function is the handle to the function to be searched, but I'm having problems implementing it. I'm gonna simplify this from my homework, but let's say I have a test function thats:
function [y] = f(x)
y = x - cos(x);
end
And my bisection root finder is:
function [root] = bisection(func, upper_bound, lower_bound)
func_ub = @func(upper_bound);
func_lb = @func(lower_bound);
root = (func_up + func_lb)/2;
end
If I enter bisection(f,0,2) in the command window matlab returns the error:
Not enough input arguments.
Error in f (line 2)
y = x - cos(x);
I'm trying to get some values for func_ub and func_lb by plugging in my upper_bound and lower_bound into my function f, some help would be greatly appreciated. Thanks!
1 Commento
Stephen23
il 30 Set 2018
Risposte (1)
Rik
il 29 Set 2018
Maybe you mean this?
bisection(@f,0,2)
4 Commenti
Jarrett Barber
il 29 Set 2018
Rik
il 29 Set 2018
You don't need the @ in the bisection function
Jarrett Barber
il 29 Set 2018
Rik
il 29 Set 2018
You're welcome. If this solved your problem, please hit the 'accept answer' button. If not, feel free to post your remaining issues in a comment below.
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