Azzera filtri
Azzera filtri

Not able to solve this expression

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Anshuman S
Anshuman S il 10 Ott 2018
Commentato: KALYAN ACHARJYA il 10 Ott 2018
I am not able to code this expression , I have tried but it's not giving correct answer ! My try is given below:
if true
sol= zeros(4,4);
s=0;
for i = 1:5
for j = 1:5
r = (j-1)*0.25 ;
fi = 2*pi*(i-1)/4 ;
disp(r)
disp(fi)
disp('r,fi')
for m1 =1:100000
s = s + (2*((r/0.03)^(2*m1))*cos(2*m1*fi)) / ((4*m1*m1 - 1)*(1 + (2*m1*40)/(20*0.03)));
end
sol(i,j)= 1/pi - (1/pi)*s + ((r/0.03)*sin(fi))/(2*(1+ (45/(20*0.03))));
end
end
disp(sol)
end
The r & phi are taken for 5 and 5 points respectively . r = 0, 0,25, 0,50, 0,75 1.0 and simillarly phi = 0, pi/2 , pi , 3pi/2 , 2pi . But my solution is coming very large than the expected value.
  4 Commenti
madhan ravi
madhan ravi il 10 Ott 2018
" for m1 =1:100000 aftermath due to this leads to more values "
Anshuman S
Anshuman S il 10 Ott 2018
it's given in the problem to take many number of terms, m1 shows the number of terms in the series, in the problem it's taken to be infinite

Accedi per commentare.

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Anshuman S
Anshuman S il 10 Ott 2018
I have solved the problem now , The r term was not within the bounds. It should be less than r0 ( 0.03 cm ) . thus r = 0.03*(j-1)*0.25 ;
Thanks for your time and help !

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