How to write to an existing column of a file?

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Kash Costello
Kash Costello il 29 Ott 2018
Modificato: per isakson il 1 Nov 2018
Hey there,
I have a .daf file here (you can open in wordpad) and you can see that there are 10 columns. I want to overwrite just the sixth column with number 1 (they're all 0's but in some rows I want to put 1). Like say on the 100th, 200th, 300th rows, I want to make them 1. I also want to save it in the same file.
How can I do that? Can someone help me?
Thank you!

Risposte (1)

per isakson
per isakson il 29 Ott 2018
Modificato: per isakson il 1 Nov 2018
AJ739_20170127115441_v2.daf is an UTF-8 encoded text file according to Notepad++.
It's close to impossible to overwrite a column in a text file.
You have to read the file and write a new file (or overwrite the old) with modified data.
In response to comments
There are many ways. This outlines a simple one.
fid_in = fopen( 'AJ739_20170127115441_v2.daf', 'r' );
fid_out = fopen( 'any_name_and_remane_later.txt', 'w+' );
str = 'anything';
while not( strcmp( str, '"***Data start***"' ) )
str = fgetl( fid_in );
fprintf( fid_out, '%s\n', str );
end
cac = textscan( fid_in, '%d...%q', 'Delimiter',',' )
fclose( fid_in )
...
fclose( fid_out )
Read about UTF-8 in the help on fopen
I'm not sure I understand "I want to overwrite just the sixth column with number 1 (they're all 0's but in some rows I want to put 1). Like say on the 100th, 200th, 300th rows, I want to make them 1." The sixth column of the uploaded file contains only zeros.
The code below writes a modified file with tab-delimited data.
fid_in = fopen( 'AJ739_20170127115441_v2.daf', 'r' );
fid_out = fopen( 'any_name_and_remane_later.txt', 'w+' );
str = 'anything';
while not( strcmp( str, '"***Data start***"' ) )
str = fgetl( fid_in );
fprintf( fid_out, '%s\n', str );
end
0,0,0,0,0,0,0,0,0,"(0)[0.00/ 0]" 252502,49,1,0,0,0,0,0,0,"Respiratory Level Error.(0)[1.87/ 488]"
cac = textscan( fid_in, '%d%d%d%d%d%d%d%d%d%q' ...
, 'Delimiter',',', 'CollectOutput',true );
fclose( fid_in );
my_data = cac{1};
str = cac{2};
The 6th column contains only zeros; all(my_data(:,6)==0) returns true
my_data(:,6) = 1;
for jj = 1 : size(my_data,1)
fprintf( fid_out, '%d\t%d\t%d\t%d\t%d\t%d\t%d\t%d\t%d\t"%s"\n' ...
, my_data(jj,:), str{jj} );
end
fclose( fid_out );
disp('Done!')
  3 Commenti
per isakson
per isakson il 31 Ott 2018
See addendum in my answer.
Kash Costello
Kash Costello il 31 Ott 2018
I saw! Thanks! What about writing the 10 columns below the string characters? I've been trying to figure that out but I don't know how to write them >.<

Accedi per commentare.

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