Multiplications inside a cell array

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Ishita Trivedi
Ishita Trivedi il 23 Gen 2019
Commentato: Guillaume il 23 Gen 2019
Capture.PNG
Hi everyone,
The above 4x12 is a cell array. Each cell contains numbers. What I want to do next is matrix multiplication between all elements of row 2 with row 4. So, (1,2)*(4,2). This will give a 33by33 matrix. Next, I want to store it in a new variable. But since this is a cell structure I am not able to do it and need help.
How can I concatenate it? Or should i convert the cell array to something else to make my life easier?
Thank you for your help.

Risposta accettata

Kevin Phung
Kevin Phung il 23 Gen 2019
use cell brackets to access contents of the cell array.
so if c is your 4x12 cell array, then c{2,1} would retun the array inside instead of the cell.

Più risposte (1)

Guillaume
Guillaume il 23 Gen 2019
Modificato: Guillaume il 23 Gen 2019
result = cellfun(@times, yourcellarray(1, :), yourcellarray(4, :), 'UniformOutput', true)
will create a 1x12 cell array of 33x33 matrices. The same implemented as a loop:
result = cell(1, size(yourcellarray, 2));
for idx = 1:size(yourcellarray, 2)
result{idx} = yourcellarray{1, idx} .* yourcellarray{4, idx};
end
If you want a 33x33x12 matrix after that:
m = cat(3, result{:})
edit: got the wrong rows
edit again: and messed up the 'UniformOutput'
  4 Commenti
Ishita Trivedi
Ishita Trivedi il 23 Gen 2019
I did end up using the loop but I would like to get more comfortable with the cell function.
As for the other answer, my for loop wasn't working because I wasn't using the curly braces - which makes sense since i needed to access the contents of the cell. I didn't explicity post what i had already tried but that was my error in the for loop. I guess it was luck but I thought Kevin figured i am having trouble because I am not accesing the contents of the cell correctly - which is true and is also clear in your answer. Thank you for you help.
Guillaume
Guillaume il 23 Gen 2019
No problem. Is cellfun clearer now?

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